How would one check if a square is within a circle?

[ivan]

I haven't looked it up, but ok I'll trust your solution, pgimeno.

[darkfrei]

If distance(corner, center)^2 > radius^2 then Return true -- at least one corner is out of circle

By cancelling the square root in distance() with the squaring above, you save four square roots. The radius^2 can be calculated once before the loop. I believe that's the protip that eliddell suggested.

I know, the (squared_distance(corner, center) > radius^2) is much faster