1K Terminal challenge

[ivan]

Goal:
Lua command line terminal

Rules:
-typed input via the keyboard
-execute commands by pressing enter
-delete characters via backspace
-do not use external files, system fonts or love's default embedded font

Extra credit:
-print results and errors on the screen
-upper and lowercase, caps
-allow printing in the terminal, ex: print("123") or print(1+2)
-shift modifier
-numeric keypad
-locals

[ivan]

Test with a large 8x8 font = 1,531 bytes:

Code: Select all

F=" 66 __ ` 66?c6f_ 0 63<_   6?n ÿ? ?   0; <_ _ 6?f3 f   6cn _ _______ 8??_ 3+<+3_ 3;0060+?0?30> 0700330_?3+0+3  ??0 _____ __>?<?<3xgcccff6FFf30fwg6{3ff306oc{3>f?0k{c{?ffs336Fcsc3ff6Ff33ffcc63?<?|3gcc________???+cc3 f3f3-+cc+ f3f+c636 >3>+kc ;8+6F0_633wcc`_8g?cc@________ ÿ  8  _   0 6 __ >0n6f7 0f3>33n6+ >f3?3fk+ 3f+>f6c+ n=n0ggc3___ _____ ___8n_____;;n>>+cc3? 6f36+c63 8 cf36+k3 c>>0,36>& c0n6c0?8 x___ ___"F=F:gsub("_","  "):gsub("+","33")O=""for a=1,#F do b=F:byte(a)for j=1,8 do h=b%2;O=O..(h>0 and"ÿÿÿÿ"or"   y")b=(b-h)/2 end end;L=love;G=L.graphics;d=L.image.newImageData(128,48,O)I=G.newImage(d)Q={}for c=0,5 do for f=0,15 do Q[#Q+1]=G.newQuad(f*8,c*8,8,8,128,48)end end;function W(g,f,c)for a=1,#g do b=g:byte(a)-31;if Q[b]then G.draw(I,Q[b],f+(a-1)*8,c)else W(g:sub(a+1),f,c+8)break end end end;O=""function L.draw()W(O.."_",0,0)end;function print(i)O=O.."\n"..tostring(i)end;Z='~!@#$%^&*()_+|{}:"<>?'z="`1234567890-=\\[];',./"function L.keypressed(k)if k=="space"then O=O.." "elseif k=="backspace"then O=O:sub(1,-2)elseif k=="return"then e=O:match("[^\n]-$")r,t=pcall(loadstring(e))O=O.."\n"..(t or"").."\n"elseif#k<2 then if L.keyboard.isScancodeDown('lshift')then j=z:find(k,1,true)k=j and Z:sub(j,j)or k;k=k:upper()end;O=O..k end end

Note: artifacts probably due to newImageData, no locals

[Ortimh]

It's so hard. I couldn't do it. I use your code, optimize it a bit, and now can use right shift for caps, with 3 bytes in extra (1,528 bytes).

Code: Select all

F=(" 66 __ ` 66?c6f_ 0 63<_   6?n ÿ? ?   0; <_ _ 6?f3 f   6cn _ _______ 8??_ 3+<+3_ 3;0060+?0?30> 0700330_?3+0+3  ??0 _____ __>?<?<3xgcccff6FFf30fwg6{3ff306oc{3>f?0k{c{?ffs336Fcsc3ff6Ff33ffcc63?<?|3gcc________???+cc3 f3f3-+cc+ f3f+c636 >3>+kc ;8+6F0_633wcc`_8g?cc@________ ÿ  8  _   0 6 __ >0n6f7 0f3>33n6+ >f3?3fk+ 3f+>f6c+ n=n0ggc3___ _____ ___8n_____;;n>>+cc3? 6f36+c63 8 cf36+k3 c>>0,36>& c0n6c0?8 x___ ___"):gsub("_","  "):gsub("+","33")O=""for a=1,#F do b=F:byte(a)for j=1,8 do h=b%2 O=O..(h>0 and"ÿÿÿÿ"or"   y")b=(b-h)/2 end end L=love G=L.graphics K=L.keyboard.isScancodeDown I=G.newImage(L.image.newImageData(128,48,O)) Q={}for c=0,5 do for f=0,15 do Q[#Q+1]=G.newQuad(f*8,c*8,8,8,128,48) end end function W(g,f,c) for a=1,#g do b=g:byte(a)-31 if Q[b]then G.draw(I,Q[b],f+(a-1)*8,c)else W(g:sub(a+1),f,c+8)break end end end O=""function L.draw()W(O.."_",0,0)end function print(i)O=O.."\n"..tostring(i)end Z='~!@#$%^&*()_+|{}:"<>?'z="`1234567890-=\\[];',./"function L.keypressed(k)k=k:gsub("space"," ")if k=="back "then O=O:sub(1,-2)elseif k=="return"then e=O:match("[^\n]-$")r,t=pcall(loadstring(e))O=O.."\n"..(t or"").."\n"elseif#k<2 then if K('lshift')or K('rshift') then j=z:find(k,1,true)k=(j and Z:sub(j,j)or k):upper()end O=O..k end end

[ivan]

Great, I'll use your version in future revisions.
It's possible to get it under 1k, if we use a smaller font - as you see from the image in the previous post 8x8 px per character is a lot.
Also, there is a "bug" with: r,t=pcall(loadstring(e)) - it doesn't print the exact Lua error, I'll see if I can fix it in the future.
Thanks for taking a look!

[DeltaF1]

I can't run this, it says "The size of the raw byte string must match the imageData's actual size in bytes."

[airstruck]

Instructions ambiguous. Here's my entry.

Code: Select all

local buffer = ''

function love.draw ()
    love.graphics.printf(buffer, 0, 0, 800)
end

function love.textinput (text)
    buffer = buffer .. text
end

function love.keypressed (key)
    if key == 'backspace' then
        buffer = buffer:gsub('[^\n]$', '')
    elseif key == 'return' then
        buffer = buffer .. '\n' ..
            io.popen(buffer:match('[^\n]*$') .. ' 2>&1'):read('*a') .. '\n'
    end
end

[ivan]

I can't run this, it says "The size of the raw byte string must match the imageData's actual size in bytes."

Might have something to do with the encoding of the .lua file so I've included a .love.

Instructions ambiguous

The point of the challenge is to make a terminal without using external/system fonts. In 1K or less.

[airstruck]

The point of the challenge is to make a terminal without using external/system fonts. In 1K or less.

I guess I did that, then.

[ivan]

Unfortunately, you used love.graphics.printf which doesn't comply with the rules.
The embedded Love2D font is around 400 k in its non-compiled form.

[airstruck]

Unfortunately, you used love.graphics.printf which doesn't comply with the rules.
The embedded Love2D font is around 400 k in its non-compiled form.

The rules don't restrict the use of love.graphics.printf or the use of the font that's packaged with love as far as I can tell. They also don't mention what the terminal is supposed to do (mine runs shell commands). The rules also don't mention anything about counting the size of assets packaged with love against the 1k character count. That's not something I'd expect given that those assets were not part of my submission. As far as I can tell, my entry complies with the rules as written.