*Solution found*

Code: Select all

```
GRID_BOTTOM_WIDTH = 768
GRID_TOP_WIDTH = 384
GRID_BOTTOM_XI = 16
GRID_BOTTOM_YI = 472
GRID_BOTTOM_XF = GRID_BOTTOM_XI + GRID_BOTTOM_WIDTH
GRID_BOTTOM_YF = GRID_BOTTOM_YI
GRID_TOP_XI = ((GRID_BOTTOM_WIDTH - GRID_TOP_WIDTH) / 2) + GRID_BOTTOM_XI
GRID_TOP_YI = 256
GRID_TOP_XF = GRID_TOP_XI + GRID_TOP_WIDTH
GRID_TOP_YF = GRID_TOP_YI
GRID_SIZE = 6
GRID_BOTTOM_STEP = GRID_BOTTOM_WIDTH / GRID_SIZE
GRID_TOP_STEP = GRID_TOP_WIDTH / GRID_SIZE
...
love.graphics.line(GRID_BOTTOM_XI, GRID_BOTTOM_YI, GRID_BOTTOM_XF,
GRID_BOTTOM_YF)
love.graphics.line(GRID_TOP_XI, GRID_TOP_YI, GRID_TOP_XF, GRID_TOP_YF)
-- Verticle lines
for i = 0, GRID_SIZE
do
love.graphics.line(GRID_BOTTOM_XI + (GRID_BOTTOM_STEP * i),
GRID_BOTTOM_YI, GRID_TOP_XI + (GRID_TOP_STEP * i), GRID_TOP_YI)
end
```

There is one possibly good technique where first you find the center of the grid. This is done by finding the intersection of the two lines that form an 'x' over the square. This will give you the y-coordinate, while the x-coordinate can possibly be found by doing stuff with the slopes of the outermost vertical lines. Then you split the square into two halves at this line and recurse on them. I hope that wasn't too vague. This approach can only give a number of lines equal to a power of 2, which may be too many.

I was thinking of using some quadratic formula for the horizontal line spacing. But then I need to invent a quadratic formula.