Can love.filesystem.read skip custom linebreaks?

[YounYokel]

Oh OK, so what you want is probably this:

Code: Select all

love.filesystem.read():gsub('\r?\n', ''):gsub('\\n', '\n')

Applied to your example:

Code: Select all

s = [[Hello World.

This is a test file which contains some text.\n

Thanks, bye!
]]
print((s:gsub('\r?\n', ''):gsub('\\n', '\n')))
--[[ prints:
Hello World.This is a test file which contains some text.
Thanks, bye!
--]]

Mind you, it doesn't work for any other escape.

Neat, it works like clockwork. Can you please share where I can learn these '\n', '\\n', '\r?', '%s', '%s$' like stuff?

[zorg]

https://en.wikipedia.org/wiki/Escape_se ... _sequences

[pgimeno]

I think the Lua manual is more relevant here, because there are some differences (most notably, that \123 takes decimal numbers instead of octal):

Patterns: see Lua manual 5.4.1 (these are only used with string.gsub, string.gmatch, string.match, string.find and the obsolete alias string.gfind)

Backslash escapes apply to every literal string, see Lua manual 2.1

(Note: The version of LuaJIT that comes with LÖVE has some Lua 5.2 extensions, including hexadecimal backslash escapes of the form \x2A, you can read about them here: LuaJIT extensions)